Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:48Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-n²) dn = √π / 2
36K
12ω² + 6ω + 7 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
131K
∑_{k=1}^{n} k = n(n+1)/2
158K
d/dn [n^4] = 4n^3
det| 7 4 ; 4 8 | = 40
376K