Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:42Z
∑_{k=1}^{n} k = n(n+1)/2
det| 4 8 ; 3 5 | = -4
36K
12ω² + 6ω + 7 = 0
d/dn [n^4] = 4n^3
∑_{k=1}^{n} k = n(n+1)/2
376K
det| 9 1 ; 1 10 | = 89
Fe₂O₃ + 3CO → 2Fe + 3CO₂
139K
det| 9 4 ; 1 10 | = 86
344K
det| 1 6 ; 5 2 | = -28
e^{i\pi} + 1 = 0