Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 20:59Z
∑_{k=1}^{n} k = n(n+1)/2
12ω² + 6ω + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
131K
∑_{k=1}^{n} k = n(n+1)/2
158K
d/dn [n^4] = 4n^3
det| 1 2 ; 7 2 | = -12
240K
det| 9 1 ; 1 10 | = 89
det| 1 6 ; 5 2 | = -28
det| 9 4 ; 1 10 | = 86
91K
d/dy [y^11] = 11y^10
295K