Spectra Ledger /sym/2e6562
id=1 · host=commstar.world · 2026-10-19 22:24Z
ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
36K
∑_{k=1}^{n} k = n(n+1)/2
269K
11β² + 9β + 0 = 0
det| 7 4 ; 4 8 | = 40
131K
ω = 2πf
det| 1 2 ; 7 2 | = -12
139K
∑_{k=1}^{n} k = n(n+1)/2
344K